Sneaky Sum of Squares

Given that 12+22+32++k2=k(k+1)(2k+1)61^2 + 2^2 + 3^2 + \ldots + k^2 = \frac{k(k+1)(2k+1)}{6}, what is the smallest integer kk such that 12+22+32++k21^2 + 2^2 + 3^2 + \ldots + k^2 is divisible by 100100?

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