# Solution, Solute and Solvent Problem 6

Chemistry Level 2

At $$18^\circ\text{C}$$, the solubility of $$\text{HgCl}_2$$ is $$6\text{ g}/100\text{ g}$$ water. At $$78^\circ \text{C}$$, the solubility is $$25\text{ g}/100\text{ g}$$ water. If a $$78^\circ \text{C}$$, saturated $$\text{HgCl}_2$$ solution is cooled down to $$18^\circ \text{C}$$ then a $$38\text{ g}$$ $$\text{HgCl}_2$$ crystal is separated from the solvent. Then, what is the mass of the original saturated $$\text{HgCl}_2$$ solution (at the time when it is at $$78^\circ \text{C}$$) in grams?

You may refer Chemistry - Solution, Solute and Solvent Note

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