Solution, Solute and Solvent Problem 6

Chemistry Level 1

At \(18^\circ\text{C}\), the solubility of \(\text{HgCl}_2\) is \(6\text{ g}/100\text{ g}\) water. At \(78^\circ \text{C}\), the solubility is \(25\text{ g}/100\text{ g}\) water. If a \(78^\circ \text{C}\), saturated \(\text{HgCl}_2\) solution is cooled down to \(18^\circ \text{C}\) then a \(38\text{ g}\) \(\text{HgCl}_2\) crystal is separated from the solvent. Then, what is the mass of the original saturated \(\text{HgCl}_2\) solution (at the time when it is at \(78^\circ \text{C}\)) in grams?

You may refer Chemistry - Solution, Solute and Solvent Note

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