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Solve by finding a combinatorial argument

Probability Level 2

$^n C_0 + ^n C_1 + ^n C_2 + ^n C_3 + ... + ^n C_{n-1} + ^n C_n =?$

1

2^{n-1}

2^n

2^{n+1}

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by Harshal Gajjar

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