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Solve for \(y\)

Algebra Level 3

\[ \dfrac{ y}{a-c} = \dfrac x{b-c} = \dfrac z{a-b} \]

Find the value of \(y\) in terms of \(a\), \(b\), \(c\), \(x\) and/or \(z\).

\[a-b\] \[a+b\] \[x+z\] \[x-z\]

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by Mounika Myla

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