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e−∣x∣+1=α \large e^{ -| x | }+1= \alphae−∣x∣+1=α
If the range of values of α\alphaα for which the above equation has no solution can be expressed as (−∞,A]∪(B,∞) \left( -\infty ,A \right] \cup \left( B,\infty \right) (−∞,A]∪(B,∞), then find the value of A+BA+B A+B.
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