\[ \large \prod_{n=2}^\infty \dfrac{n^3-1}{n^3 + 1} = \dfrac79 \times \dfrac{26}{28} \times \dfrac{63}{65} \times \cdots \times \dfrac{n^3-1}{n^3+1} \times \cdots \]

Compute the infinite product above to 2 decimal places.

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