# Solve the Equation (bonus question)(free rating)

**Algebra**Level 2

The sum of 3 numbers is 9.

If we multiply third number by 3 and add to the second number, we get 16.

By adding the first and the third number and then subtracting twice the second number from this sum,we get 6

Find the value of\( (xy+yz+zx)(xyz)(x^2+y^2+z^2)\)