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Given that f(x)=mx+bf(x) = mx+bf(x)=mx+b such that f(2)=0f(2)=0f(2)=0, f(x1)=f1f(x_1)=f_1f(x1)=f1, and f(x2)=f2f(x_2)=f_2f(x2)=f2. Find the value of f1x2−f2x1f1−f2. \frac{f_1x_2 - f_2x_1}{f_1-f_2}.f1−f2f1x2−f2x1.
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