# Some function

Algebra Level 4

$f\left( 1+\frac { \sqrt { 2 } }{ x } \right) =\frac { \left( 1+\sqrt { 2017 } \right) { x }^{ 2 }+2\sqrt { 2 } x+2 }{ { x }^{ 2 } } ,\quad x\neq 0$

Let function $$f$$ be defined as above. Find the value of $$f\left( \sqrt { 2018-\sqrt { 2017 } } \right)$$

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