Some Mistakes can give rise to problem

Calculus Level 5

2e+43e3+65e5+=?\large{\frac { 2 }{ e } +\frac { 4 }{ 3{ e }^{ 3 } } +\frac { 6 }{ 5{ e }^{ 5 } } + \cdots = \, ? }

Bonus:Generalize for

n=1m2n(2n1)e(2n1)\large{\sum _{ n=1 }^{ m }{ \frac { 2n }{ \left( 2n-1 \right) { e }^{ \left( 2n-1 \right) } } } }

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