# Soviet Trig Eqn. 2

Geometry Level 4

Solve, for $$0^{\circ} < x < 90^{\circ}$$, the following equation for $$x$$:

$\sqrt{2-2\cos x}+\sqrt{10-6\cos x}=\sqrt{10-6\cos 2x}$

If $$x$$ can be represented in the form $$\arccos\left( \dfrac{a-\sqrt{b}}{c}\right)$$, find $$a+b+c$$.

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