Split Summation

Calculus Level 4

True or False? n=11n(n+1)=n=11nn=11n+1 \sum_{n=1}^\infty \frac{1}{n(n+1) } = \sum_{n=1}^\infty \frac{1}{n} - \sum_{n=1}^\infty \frac{1}{n+1}

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