"Spoooooooky" Russian rational expressions 6

Algebra Level 2

E=(ab2ab+ba2ab)(abba) \mathscr{E} = \left( \dfrac{a}{b^2 - ab} + \dfrac{b}{a^2 -ab} \right) \left( \dfrac{ab}{b-a} \right)

Let a=2017 a = 2017 and b=2016 b = 2016 . Find the exact value of E \mathscr{E} .


Credit: My former Trig teacher's worksheet of Russian rational expressions
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