SquareRoot (Taylor Series)

Calculus Level 2

Determine the first 3 terms of the Taylor series for the function $f(x) = \sqrt{x} \text{ centered at } x = 9.$

3 + \frac{1}{6}(x - 9) - \frac{1}{108}(x - 9)^2

3 + \frac{1}{6}(x - 9) + \frac{1}{108}(x - 9)^2

3 + \frac{1}{6}(x - 9) - \frac{1}{216}(x - 9)^2

3 + \frac{1}{6}(x - 9) + \frac{1}{216}(x - 9)^2