Squeezy fractions

Suppose \(a, b\) are positive integers satisfying:

\( \frac {27}{197} < \frac {a}{b} < \frac {41}{299} \).

Let \(B\) (a positive integer) be the minimum value of \(b\) such that there exists a positive integer value of \(a\), say \(A\) , such that this equation is satisfied.

Let D ( a positive integer) be the minimum value of d such that there exists a positive integer value of \(c\) , satisfying the following inequality:

\( \frac {27}{197} < \frac {c}{d} < \frac {A}{B} \).

Evaluate \(B+D\).

×

Problem Loading...

Note Loading...

Set Loading...