A mathlete has been tracking the percentage of problems he has gotten right so far this season.

Let \(n\) be the number of problems given to him, and \(m\) the number he has gotten correct.

Find the sum of all \(0<q<0.85\) such that if at some point in the season \(\frac{m}{n}<q\), and at some **later** point in the season \(\frac{m}{n}>q\), then there will **always** be a third point in the season where \(\frac{m}{n}=q.\)

If you believe that no such \(q\) exists, submit \(-1\) as your answer.

**Clarification**: Although it is true that *any* rational \(q\) may be obtained after the first two points, the problem requires that this rational \(q\) *must* exist at some point in the season. In particular, it might be helpful to analyze points in the season *between* the two points satisfying the first two conditions.

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