String, bob and a circle!

The upper end of the string of a simple pendulum is fixed to a vertical \(z\)-axis,and set in motion such that the bob moves along a horizontal circular path of radius \(2\text{ m}\), parabola to the \(xy\) plane, \(5\text{ m}\) above the origin. The bob has a speed of \(3 \text{ m/s}\).The string breaks when the bob is vertically above the \(x\)-axis, and lands on the \(xy\) plane at a point \((x,y)\).

Find \(x+y\).

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