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The roots of the equation 3x2(x2+8)+16(x3−1)=0{ 3x }^{ 2 }({ x }^{ 2 }+8)+16({ x }^{ 3 }-1)=03x2(x2+8)+16(x3−1)=0 are not all unequal : The sum of all 4 roots is −ab-\frac { a }{ b }−ba .
where a and b are Co Primes. Find a + b
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