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arctan(13)+arctan(14)+arctan(15)+arctan(1n)=π4\arctan\left(\frac {1}{3} \right)+ \arctan\left(\frac {1}{4}\right) + \arctan\left(\frac {1}{5} \right)+ \arctan\left(\frac {1}{n} \right)= \frac {\pi}{4}arctan(31)+arctan(41)+arctan(51)+arctan(n1)=4π
Find the positive integer nnn such that it satisfy the equation above.
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