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The sum ∑n=14log0.5321nlog0.58n+2\sum_{n=1}^4 \frac{ \log_{0.5}32^{\frac{1}{n}}}{ \log_{0.5}8^{n+2}}n=1∑4log0.58n+2log0.532n1 equals:
This question was taken from ITA (Instituto Tecnológico da Aeronáutica) Brazil 2013-2014 entrance exam.
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