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For all real values of θ\thetaθ for which ∣sinθ∣≠1,\lvert \sin \theta \rvert \neq 1,∣sinθ∣=1, evaluate:
∑n=1∞sin2nθ.\large \sum_{n = 1}^{\infty} \sin^{2n}\theta . n=1∑∞sin2nθ.
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