Sum of squares of divisors

Let \(n\) be a natural number.

Suppose \(d_{1},d_{2},d_{3}, \ldots \) are the divisors of \(n\) such that

\(1=d_{1}<d_{2}<d_{3}<\ldots \)

Suppose \(n=d_{1}^{2}+d_{2}^{2}+d_{3}^{2}+d_{4}^{2}\)

Find the value of \(n\).

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