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∑k=1681⌊x+k100⌋=625\large \sum_{k=16}^{81} \left \lfloor x+\frac{k}{100} \right \rfloor =625 k=16∑81⌊x+100k⌋=625 If xxx is a positive number that satisfy the summation above, evaluate ⌊100x⌋ \lfloor 100x \rfloor ⌊100x⌋.
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