Sum them all up! (3)

Calculus Level 5

\[\displaystyle \large{ \sum_{\text{$\tau(n)$ is even}} \frac{1}{n^2} }\]

The sum runs over all positive integers \(n\) where \(\tau(n)\), the number of positive divisors of \(n\), is even. Find the value of the sum.


This is part of set Sum up all of them!
×

Problem Loading...

Note Loading...

Set Loading...