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∑n=120151(n+n+1)(n4+n+14)\large \sum_{n=1}^{2015} \dfrac{1}{(\sqrt{n} + \sqrt{n+1})(\sqrt[4]{n} + \sqrt[4]{n+1})}n=1∑2015(n+n+1)(4n+4n+1)1
If the above summation can be expressed as ab4−ca\sqrt[4]{b}-ca4b−c where a,b,ca,b,ca,b,c are positive integers and bbb is free of fourth power, find the value of a+b+ca+b+ca+b+c.
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