# Sum to 2016

Algebra Level pending

$\left \lfloor{\sqrt{6}}\right \rfloor +\left \lfloor{\sqrt{7}}\right \rfloor+\left \lfloor{\sqrt{8}}\right \rfloor+\ldots+\left \lfloor{\sqrt{n}}\right \rfloor=2016$

Find the value of the integer $$n$$, satisfying the above equation.

Inspiration

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