Sum to 2016

Algebra Level pending

\[\left \lfloor{\sqrt{6}}\right \rfloor +\left \lfloor{\sqrt{7}}\right \rfloor+\left \lfloor{\sqrt{8}}\right \rfloor+\ldots+\left \lfloor{\sqrt{n}}\right \rfloor=2016\]

Find the value of the integer \(n\), satisfying the above equation.


Inspiration

×

Problem Loading...

Note Loading...

Set Loading...