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[∑n=110∫−2n−1−2nsin27x dx]+[∑n=110∫2n2n+1sin27x dx]= ?\left[\displaystyle\sum_{n=1}^{10}\displaystyle\int_{-2n-1}^{-2n}\text{sin}^{27} \text{x dx}\right]+ \left[\displaystyle\sum_{n=1}^{10} \displaystyle\int_{2n}^{2n+1}\text{sin}^{27} \text{x dx}\right] = \ ?[n=1∑10∫−2n−1−2nsin27x dx]+[n=1∑10∫2n2n+1sin27x dx]= ?
Answer upto two decimals.
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