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∑k=32000k(k−2)!+(k−1)!+k! \sum_{k=3}^{2000} \frac{k}{(k-2)! + (k-1)! + k!} k=3∑2000(k−2)!+(k−1)!+k!k
Which of the following choices is the best approximation for the summation above?
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