Now, what familiar equations can I use?

Calculus Level 3

n=1(11e)nn= ?\large\displaystyle\sum_{n=1}^{\infty}\frac{\left(1-\frac{1}{e}\right)^n}{n}=\ ?

With e=m=01m!2.71828\displaystyle e = \sum_{m=0}^\infty \frac1{m!} \approx 2.71828 .

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