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∑m=1∞[tan−1(3m2−3m+1m6−3m5+3m4−m3+1)]= ?\large \sum_{m=1}^{\infty} \left [ \tan^{-1} \left (\frac{3m^2-3m+1}{m^6-3m^5+3m^4-m^3+1} \right ) \right ] = \ ? m=1∑∞[tan−1(m6−3m5+3m4−m3+13m2−3m+1)]= ?
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