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If ∑n=1∞n22n=S\displaystyle \sum_{n=1}^\infty \frac{ n^2 } { 2^n } = S n=1∑∞2nn2=S, and f(x)=x+x+x+x+… f(x) = \sqrt{ x + \sqrt{ x + \sqrt{ x + \sqrt{ x + \ldots}}}} f(x)=x+x+x+x+…, find f(S) f(S) f(S).
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