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The formula for the sum of the first nnn terms of an arithmetic progression is given by Sn=n(2a1+(n−1)d)2S_n = \dfrac{n(2a_1 + (n-1)d)}2 Sn=2n(2a1+(n−1)d).
Find the sum of the first 6 terms when a1=−2a_1 =-2a1=−2 and d=3d= 3 d=3.
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