$\lim_{n \to \infty} \dfrac{\displaystyle\sum abcde}{n^{10}}=\dfrac{A}{B}$

subject to the condition that $1 \leq a \leq b \leq c \leq d \leq e \leq n$. Find $A+B$.

$\textbf{Note :} \ A,B$ are co-prime integers. The answer is exact, not an approximation.

×

Problem Loading...

Note Loading...

Set Loading...