# Summing The Series

Algebra Level 4

$\dfrac{4\times{3}\times{2}\times{1}}{3!+2!+1!}$+$\dfrac{5\times{4}\times{3}\times{2}}{4!+3!+2!}$+.......+$\dfrac{2015\times{2014}\times{2013}\times{2012}}{2014!+2013!+2012!}$= $a$

Find $\lfloor{a}\rfloor$

$\lfloor...\rfloor$ is the greatest integer less than equal to [$...$]

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