Summing The Triangle

$\begin{array}{c} 1 \end{array} \\ \begin{array}{cc} 1 & 1 \end{array} \\ \begin{array}{ccc} 1 & 2 & 1 \end{array} \\ \begin{array}{cccc} 1 & 3 & 3 & 1\end{array} \\ \begin{array}{ccccc} 1 & 4 & 6 & 4 & 1\end{array} \\ \begin{array}{cccccc} \vdots & \hphantom{\vdots} & \vdots & \hphantom{\vdots} & \vdots \end{array} \\$

Pascal's triangle is shown above for the $0^\text{th}$ row through the $4^\text{th}$ row.

What is the sum of all the elements in the $12^\text{th}$ row?

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Note: The topmost row in Pascal's triangle is the $0^\text{th}$ row. Then, the next row down is the $1^\text{st}$ row, and so on.