Consider a spring with negligible mass that has an unstretched length \( l_{0} = 8.8 \times 10^{-2} \text{ m} \). A body of mass \( m_{1} =1.5 \times 10^{-1} \text{ kg } \) is suspended from one end of the spring. The other end of the spring is fixed. After a series of oscillations has died down, the new stretched length of the spring is \( l = 9.8 \times 10^{-2} \text{ m} \).

Assuming that the spring satisfies Hooke’s Law when stretched, what is the spring constant?

×

Problem Loading...

Note Loading...

Set Loading...