Suspicious Quadrilateral

Geometry Level 4

In a quadrilateral \(ABCD\), \(m\angle CAD = \dfrac{1}{2} m\angle CBD = \dfrac{1}{3} m\angle BAC = \dfrac{1}{4} m\angle ABD = 12^\circ\). Find \(m\angle ACD\).

Note: Illustration not necessarily drawn to scale.

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