Sylow and 168

Let GG be a simple group with 168 elements. How many elements of order 7 does GG contain?

Notation: An element gGg\in G has order 7 if g7=1g^7 = 1 but gx1g^x \ne 1 for any positive integer x<7.x<7. (Here 11 is the identity of the group G.G.)

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