\[\large\begin{cases} x^3+3y^3-xy^2=1 \\ x^4+6y^4=x+2y\end{cases}\]
Let \((x_1;y_1),(x_2;y_2),...,(x_n;y_n)\) be the solutions to the system above, calculate \(\displaystyle\sum_{m=1}^{n} x_m+y_m\) (up to 2 decimal places)

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