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x+1yz=15y+1xz=−115z+1xy=13\large{\begin{aligned}x+\dfrac{1}{yz} &= \dfrac{1}{5}\\ y+\dfrac{1}{xz} &= -\dfrac{1}{15}\\ z+\dfrac{1}{xy} & =\dfrac{1}{3} \end{aligned}}x+yz1y+xz1z+xy1=51=−151=31 If x,yx,yx,y and zzz are real numbers which satisfy the given equations above, find z−yz−x\dfrac{z-y}{z-x}z−xz−y.
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