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log225x+log64y=4logx225−logy64=1\begin{aligned} \large\log_{225}x+\log_{64}y&=&\large4 \\ \large\log_{x}225-\log_{y}64&=&\large1 \end{aligned} log225x+log64ylogx225−logy64==41
The solutions to the system of equations above are (x1,y1)(x_1,y_1)(x1,y1) and (x2,y2)(x_2,y_2)(x2,y2) . Find log30(x1y1x2y2)\log_{30}\left(x_1y_1x_2y_2\right)log30(x1y1x2y2).
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