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an=1+(1+1n)2+1+(1−1n)2\large a_n=\sqrt{ 1+\left(1+\dfrac{1}{n} \right)^2 }+\sqrt{ 1+\left(1-\dfrac{1}{n} \right)^2 }an=1+(1+n1)2+1+(1−n1)2
Consider a sequence ana_nan, n≥1n\geq1n≥1 as defined above. Compute 1a1+1a2+⋯+1a20\dfrac{1}{a_1}+\dfrac{1}{a_2}+\cdots+\dfrac{1}{a_{20}}a11+a21+⋯+a201.
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