Television Chances

Probability Level 1

Let XX be the number of televisions for a household chosen randomly. It is given that

P(X=1)=0.18,P(X=2)=0.36,P(X=3)=0.34,P(X=4)=0.08,P(X=5)=0.04. \begin{aligned} P(X=1) & = 0.18, \\ P(X=2) & = 0.36, \\ P(X=3) & = 0.34, \\ P(X=4) & = 0.08, \\ P(X=5) & = 0.04. \end{aligned}

If P(X<5)=aP(X < 5) = a, what is the value of 100a100a?

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