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If Sn=∑r=1ntr=2n3+9n2+13n6S_n=\displaystyle\sum_{r=1}^{n} t_{r} = \dfrac{2n^3+9n^2+13n}{6}Sn=r=1∑ntr=62n3+9n2+13n for all positive integers nnn, evaluate ∑r=110tr\displaystyle\sum_{r=1}^{10} \sqrt{t_r} r=1∑10tr.
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