# That is close 2

A particle is projected up an inclined plane of base angle $$\alpha$$ with the horizontal with an initial velocity $$V$$. The particle collides elastically with the incline and rebounds vertically . If the particle reaches back the point of projection after time
$$\large T = \dfrac {aV}{g \sqrt{1+b\sin^2\alpha}}$$, then enter the value of$$a + b$$ .

Note: $$g$$ denotes the acceleration due to gravity.

Assume the inclined plane is fixed to the ground.

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