# That would take a long time for us to calculate!!Instead,let's try something else.

Level pending

Let $$A=\dfrac{2}{1*3}+\dfrac{2}{3*5}+\dfrac{2}{5*7}+\dfrac{2}{7*9}+\dfrac{2}{9*11}$$ and let $$B=\dfrac{1}{1*2}+\dfrac{1}{2*3}+\dfrac{1}{3*4}+\dfrac{1}{4*5}+\dfrac{1}{5*6}+\dfrac{1}{6*7}+\dfrac{1}{7*8}$$,then evaluate $$33A-32B$$.

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