That's one big number!

Let NN be the number that consists of 61 consecutive 3's, so N=333333613sN = \underbrace{333\ldots333}_{61 \, 3's}. Let MM be the number that consists of 62 consecutive 6's, so M=6666666626sM=\underbrace{6666\ldots666}_{62 \, 6's}. What is the digit sum of N×MN\times M?

Details and assumptions

The digit sum of a number is the sum of all its digits. For example the digit sum of 1123 is 1+1+2+3=71 + 1 + 2 + 3 = 7.

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