The \(n^{\text{th}}\) term of a series \(1+\frac{1}{6}+\frac{1}{72}+...\) is given by \(a(\frac{1}{4})^n+b(\frac{1}{3})^n\). Find the sum to infinity of the series.

Where, \(a\) and \(b\) are integers

NB: The answer will be in the form of \(\frac{c}{d}\). Express it as \(10c+d\)

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