# That's some series you got there

Algebra Level pending

The $$n^{\text{th}}$$ term of a series $$1+\frac{1}{6}+\frac{1}{72}+...$$ is given by $$a(\frac{1}{4})^n+b(\frac{1}{3})^n$$. Find the sum to infinity of the series.

Where, $$a$$ and $$b$$ are integers

NB: The answer will be in the form of $$\frac{c}{d}$$. Express it as $$10c+d$$

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