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∑x=1∞[ln(x+4x)−ln(x+6x+2)]=ln(a)\displaystyle \sum_{x=1}^{\infty} \left [ \ln\left(\dfrac{x+4}{x}\right)-\ln\left(\dfrac{x+6}{x+2}\right) \right ] =\ln(a)x=1∑∞[ln(xx+4)−ln(x+2x+6)]=ln(a)
Evaluate the following sum above and solve for the value of aaa.
Try the harder version here
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