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How many positive integers mmm are there, such that for some triple of positive integers (a,b,c) (a, b, c) (a,b,c), we have
m=ab+bc+ca? m = \frac{ a}{b} + \frac{b}{c} + \frac{c}{a}? m=ba+cb+ac?
For example, if a=b=c a = b = c a=b=c, then we get the value 11+11+11=3 \frac{1}{1} + \frac{1}{1} + \frac{1}{1} = 3 11+11+11=3.
Hence, the answer is "at least 1", which applies to all 4 options. You need to figure out which is correct.
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