The Answer Is At Least 1

How many positive integers mm are there, such that for some triple of positive integers (a,b,c) (a, b, c) , we have

m=ab+bc+ca? m = \frac{ a}{b} + \frac{b}{c} + \frac{c}{a}?


For example, if a=b=c a = b = c , then we get the value 11+11+11=3 \frac{1}{1} + \frac{1}{1} + \frac{1}{1} = 3 .

Hence, the answer is "at least 1", which applies to all 4 options. You need to figure out which is correct.

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